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Mathematics 15 Online
OpenStudy (anonymous):

Evaluate cos(tan^-1 0).

OpenStudy (shubhamsrg):

well if tan x =0//what is is x if x lies between (-pi/2 to pi/2) ?

OpenStudy (anonymous):

cos(arcTan(0))=1

OpenStudy (anonymous):

arcTan(0)=0

OpenStudy (anonymous):

I miss you

OpenStudy (anonymous):

you should actually work through this from the inside and work to the outside as @shubhamsrg was doing.

OpenStudy (anonymous):

i miss u too.

OpenStudy (anonymous):

????

OpenStudy (anonymous):

YAY

OpenStudy (anonymous):

lol

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