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Physics 27 Online
OpenStudy (anonymous):

?please and thankyou. A gamma ray with an energy of 3.40 × 10-14 joules strikes a photographic plate. We know that Planck's constant is 6.63 × 10-34 joule·seconds. What is the frequency of the photon? A. 5.13 × 1019 hertz B. 5.60 × 1017 hertz C. 2.45 × 1017 hertz D. 2.45 × 10-12 hertz E. 7.80 × 10-19 hertz

OpenStudy (anonymous):

how would i solve this?

OpenStudy (anonymous):

ans is A USE THE FORMULAE E=hf

OpenStudy (anonymous):

thanks

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