The area of the figure below is (4x + 2)(4x + 3). Find another expression for this area by finding the sum of the areas of the smaller rectangles. 16x^2 + 20x + 6 16x^2 + 16x + 6 16x + 10 64x^2 + 80x + 24
looking at your figure the and 4 reactangles(squares) find the areas of each grey = \[4x \times (4x+1) = 16x^2 4x\] bottom white \[2 \times 4x = 8x\] right white \[2 \times (4x + 1) = 8x + 2\] black \[2 \times 2 = 4\] sum the areas \[16x^2 + 4x + 8x + 8x + 2 + 4 = 16x^2 + 20x + 6\]
the 1st area is \[16x^2 + 4x\]
It isnt a choice
can you please read the solution as the 1st area I found is missing an a plus sign... so I posted the correct expression to help you understand...
Oh ok sorry. Thanks
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