Question

Solve this system of equations. Hint: Use graphing, substitution, or elimination to find the points (x,y) that make both equations true.
PIC ATTACHED

Answer 1

since y = x^2 - 5 then plug it in for the other equation

-3x+ y = -7
-3x+ (x^2 - 5) = -7

then it becomes

x^2 -3x - 5 =-7

x^2-3x +2= 0

(x - 1) (x- 2) =0

x-1 = 0 or x-2=0
x=1 x=2

Answer 2

to solve for y plug in x= 1 and then x=2

into y= x^2 -5