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Solve this system of equations. Hint: Use graphing, substitution, or elimination to find the points (x,y) that make both equations true. PIC ATTACHED
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since y = x^2 - 5 then plug it in for the other equation -3x+ y = -7 -3x+ (x^2 - 5) = -7 then it becomes x^2 -3x - 5 =-7 x^2-3x +2= 0 (x - 1) (x- 2) =0 x-1 = 0 or x-2=0 x=1 x=2
to solve for y plug in x= 1 and then x=2 into y= x^2 -5
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