What are the solutions of 3x2 + 4x = –5? the quantity negative 4 plus or minus i square root of 66 all over 6 the quantity negative 2 plus or minus 2i square root of 66 all over 3 the quantity negative 2 plus or minus i square root of 11 all over 3 the quantity negative 4 plus or minus i square root of 11 all over 6
Did you put it equal to 0 and plug into the quadratic formula?
3x^2+4x+5=0
3x^2 + 4x = –5 3x^2 +4x +5 =0 Now, use the quadratic formula for the equation. \[x= \frac{-b \pm \sqrt{b^2 -4ac}}{2a}\] Put a =3, b=4 and c=5 into the formula. Can you do it?
is it the first option?
the quantity negative 4 plus or minus i square root of 66 all over 6?
Not really... Just consider the determinant b^2 - 4ac For a =3, b=4 and c=5 , b^2 - 4ac = 4^2 - 4 (3) (5) = 16 - 60 = ?
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