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A parabola has equation y - 7 = 3(x + 2)^2. Rewrite the equation in the form Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0.
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Expand the binomial (x+2)^2 , put all terms on the left and in the proper order. Use 0 for a coefficient if there is no such term.
what about the -7?
check me, please: 3x^2+12x+-1y+19=0
Hang on. I will.
y-7=3(x+2)^2= y-7=3(x^2+4x+4) y-7=3x^2+12x+12 3x^2+12x-y+19=0
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Yep. I agree.
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