Solve the system by the addition method:
2x-y=10
6x+4y=-8

This is what I get:
8x-4y=40
6x+4y=-8
14x=32

Of course when I try to divide these and solve for x I get some crazy decimal that isn't a solution at all.

Question

Solve the system by the addition method:
2x-y=10
6x+4y=-8

This is what I get: 
8x-4y=40 
6x+4y=-8
14x=32

Of course when I try to divide these and solve for x I get some crazy decimal that isn't a solution at all.

pfenn1 · Answer

I think your answer for x is actually correct.  Leave it as a fraction 32/14=16/7.  Now solve for y.

anonymous · Answer

looks good to me as well
to hell with the decimals, work with the fractions

nali · Answer

do u still need help

anonymous · Answer

Alright, I will trying working it as a fraction and see what I can come up with. Thank you.

nali · Answer

u r welcome

anonymous · Answer

The fractions seem to have done the trick. I just was not thinking in terms of fractions. Thank you guys for all the help!! :)