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A square with a side of 20 is decreased to a side of 16. By how much is the diagonal decreased? s it just 4
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when the side is 20 the diag length is 20 root 2 when the side is 16 the diag length is 16 root 2 therefore it has decreased by 4root 2 length
by Pythagoras theorem :- big square's diagonal=\[20\sqrt{2}\] small square's diagonal=\[16\sqrt{2}\]
now subtract them:- u will get \[4\sqrt{2}\]
o ok yeah i knew it wouldnt be as simple as 4 thank u
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