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Mathematics

OpenStudy (anonymous):

âˆšx + 14 - 12 = x

OpenStudy (anonymous):

x is either 2 or -1

OpenStudy (anonymous):

i was gonnea say the same

OpenStudy (anonymous):

too slow!

OpenStudy (anonymous):

hehehehe

OpenStudy (anonymous):

my comp is freazing every once in a wile thats y

OpenStudy (anonymous):

But 2 or -1 doesn't show :(

OpenStudy (anonymous):

square both sides and then rearrange so it gives x^2-x-2=0 then you factorise to give (x-2)(x+1) hence x is 2 or -1

OpenStudy (anonymous):

how old r u btw

OpenStudy (anonymous):

I'm 10, I'm a mathematical god

OpenStudy (anonymous):

i am 11

OpenStudy (anonymous):

those aren't options

OpenStudy (anonymous):

cococnutshake do u have facebook

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Thanks for the help!

OpenStudy (anonymous):

your welcom jk

OpenStudy (anonymous):

Coconutshake, if you square:\[\sqrt{x}+14-12=x\],\[\sqrt{x}+2=x\]wouldnt' you get \[x+4=x^{2}\] Therefore the equation\[x^{2}-x-4=0\]

OpenStudy (anonymous):

ekk that should be \[x^{2}-4x+4=0 \]

OpenStudy (anonymous):

Therefore the answer is 2.

OpenStudy (anonymous):

Therefore your answer is wrong

OpenStudy (anonymous):

x = -10 and x = -13 is the correct answer

OpenStudy (anonymous):

You're actually all incorrect. |dw:1338055044817:dw|

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