Mathematics
OpenStudy (anonymous):

whats is the simplified form of 4z^2+16+15/2z^2-z-16

OpenStudy (anonymous):

factor out what you can on both the top and bottom

OpenStudy (anonymous):

Which in this case is not much,....

OpenStudy (anonymous):

try to factore the bottom trinomial

jhonyy9 (jhonyy9):

from the 16 you have missed a z ,yes ?

OpenStudy (anonymous):

Hmm that might make more sense :P

jhonyy9 (jhonyy9):

in numerator

OpenStudy (anonymous):

Oh I missed that. yes there is a z after 16

jhonyy9 (jhonyy9):

ok than do you know how you solve a quadratic equation ?

jhonyy9 (jhonyy9):

the formula of discriminant ?

OpenStudy (anonymous):

not nessecary...

OpenStudy (anonymous):

use decomposition factoring on top

jhonyy9 (jhonyy9):

so than do it without

OpenStudy (anonymous):

Okay thank you.:) I'm just not very good at factoring so I wasn't sure how.

OpenStudy (anonymous):

Do you have an idea about the factoring on top?

OpenStudy (anonymous):

ill give you a hand

OpenStudy (nali):

do u still need help?

OpenStudy (anonymous):

Yes, I thought I got it but I didn't... so yes please

OpenStudy (nali):

ok jsut give a few minutes

OpenStudy (nali):

4z^2+16+15/2z^2-z-16 just as Bitmaximus had stated earlier factor both expressions then it will be simplified

OpenStudy (nali):

factor 4z^2 + 16 z + 15 (2z+3)(2z +5) then factor the bottom trinomial 2z^2 - z - 16

OpenStudy (nali):

do u see what i am doing?

OpenStudy (anonymous):

Yeah I'm following so far

OpenStudy (nali):

so try and factor 2z^2 - z - 16

OpenStudy (anonymous):

wouldn't my answer be 2z+3 over z-3

OpenStudy (nali):

u mean for the final answer

OpenStudy (anonymous):

OpenStudy (nali):

ok let me check first

OpenStudy (nali):

the simpllified form is (2z+3) ( 2z+5) / 2z^2-z-16

OpenStudy (nali):

even though it is not the same as ur answer, but the problem is that u can not factor the bottom trinomial

OpenStudy (nali):

are u still with me?

OpenStudy (anonymous):

Yeah I tried to factor the bottom it doesn't make that much sense

OpenStudy (nali):

that is why i think that ^^ is the simplified form

OpenStudy (anonymous):