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For a segment of a radio show a DJ can play 9 records. If there are 12 records to select from, in how many ways can the program for this segment be arranged.
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See, we choose 9 from 12, so it'd be 12 choose 9 aka 12c9.
Do you know what combinations are?
This is similar to the last problem There are 12 choices for the first slot There are 11 choices for the second slot etc etc until you get to 3 choices for the 9th slot
Basically, nCr is: \(\Large \color{MidnightBlue}{\Rightarrow {n! \over (n - r)! r!} }\)
yes its sure been a while since i dont problems like this. thanks for the replys.
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what do i multipy thats whats throwing me off
\[ \large \binom{12} 9 = \binom{12} 3= 220 \]
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