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SOlve: 3x^2 = 147
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x^2=49 x=+/-7
Divide both sides by 3. \(\Large \color{MidnightBlue}{\Rightarrow x^2 = 49 }\) Find the sqrt of both sides.
So x = 7
or -7
Or would it be x = 7 and x = -7
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+7 and -7, both will be roots of this equation
Yea, or you could say: \(\Large \color{MidnightBlue}{\Rightarrow x = \pm7 }\)
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