Mathematics OpenStudy (anonymous):

Solve: x^2 - 7x = -12 OpenStudy (anonymous):

use middle term factor process OpenStudy (anonymous):

Got it! =5 and 4 OpenStudy (anonymous):

no, 3 and 4 check it out again OpenStudy (pfenn1):

$x^2-7x+12=0$Can either factor or might be just as easy to use the quadratic equation.$ax^2+bx+c=0$$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$ OpenStudy (anonymous):

apply the concept correctly Parth (parthkohli):

Add 12 to both sides. $$\Large \color{MidnightBlue}{\Rightarrow x^2 - 7x + 12 }$$ A quadratic equation is ax^2 + bx + c = 0 According to that, the formula is: $$\Large \color{MidnightBlue}{\Rightarrow x = {-b \pm \sqrt{b^2 - 4ab} \over 2a} }$$ OpenStudy (anonymous):

Here's a nother problem i'm not sure on... Quadratic equations can be solved using the quadratic formula... Always, sometimes, or never.. I think its sometimes OpenStudy (anonymous): Parth (parthkohli):

Always...they can be....unless there's no solution OpenStudy (anonymous):

always there is solution.. no unless is there thing is that the roots may be real or imaginary depending on the equation Parth (parthkohli):

No solution here means no real solution. There may be a complex one. OpenStudy (anonymous):

but if a particular set is specified, then the answer will be 'sometimes' OpenStudy (anonymous): OpenStudy (anonymous):

i got the answer x = -2 + or - √32 all over 2 Parth (parthkohli):

There's always the quadratic formula :D OpenStudy (anonymous):

use the quadratic formula again...... simple Parth (parthkohli):

You can look at wolframalpha to check it. OpenStudy (anonymous):

i got the answer x = -2 + or - √32 all over 2

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