Solve: x^2 - 7x = -12

use middle term factor process

Got it! =5 and 4

no, 3 and 4 check it out again

\[x^2-7x+12=0\]Can either factor or might be just as easy to use the quadratic equation.\[ax^2+bx+c=0\]\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

apply the concept correctly

Add 12 to both sides. \(\Large \color{MidnightBlue}{\Rightarrow x^2 - 7x + 12 }\) A quadratic equation is ax^2 + bx + c = 0 According to that, the formula is: \(\Large \color{MidnightBlue}{\Rightarrow x = {-b \pm \sqrt{b^2 - 4ab} \over 2a} }\)

Here's a nother problem i'm not sure on... Quadratic equations can be solved using the quadratic formula... Always, sometimes, or never.. I think its sometimes

x= 3 and 4... http://www.wolframalpha.com/input/?i=x%5E2+-+7x+%3D+-12

Always...they can be....unless there's no solution

always there is solution.. no unless is there thing is that the roots may be real or imaginary depending on the equation

No solution here means no real solution. There may be a complex one.

but if a particular set is specified, then the answer will be 'sometimes'

What about this one... What are the solutions of x^2 + 2x + 9

i got the answer x = -2 + or - âˆš32 all over 2

There's always the quadratic formula :D

use the quadratic formula again...... simple

You can look at wolframalpha to check it.

i got the answer x = -2 + or - âˆš32 all over 2