Solve: x^2 - 7x = -12
use middle term factor process
Got it! =5 and 4
no, 3 and 4 check it out again
\[x^2-7x+12=0\]Can either factor or might be just as easy to use the quadratic equation.\[ax^2+bx+c=0\]\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
apply the concept correctly
Add 12 to both sides. \(\Large \color{MidnightBlue}{\Rightarrow x^2 - 7x + 12 }\) A quadratic equation is ax^2 + bx + c = 0 According to that, the formula is: \(\Large \color{MidnightBlue}{\Rightarrow x = {-b \pm \sqrt{b^2 - 4ab} \over 2a} }\)
Here's a nother problem i'm not sure on... Quadratic equations can be solved using the quadratic formula... Always, sometimes, or never.. I think its sometimes
Always...they can be....unless there's no solution
always there is solution.. no unless is there thing is that the roots may be real or imaginary depending on the equation
No solution here means no real solution. There may be a complex one.
but if a particular set is specified, then the answer will be 'sometimes'
What about this one... What are the solutions of x^2 + 2x + 9
i got the answer x = -2 + or - √32 all over 2
There's always the quadratic formula :D
use the quadratic formula again...... simple
You can look at wolframalpha to check it.
i got the answer x = -2 + or - √32 all over 2
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