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Mathematics
OpenStudy (anonymous):

Can someone help me with this algebra?

OpenStudy (anonymous):

Is there anyone who is very good at algebra with factoring by using trial factors

OpenStudy (anonymous):

the problem is 2x2+3x+1

OpenStudy (anonymous):

\[2x^{2}+3x+1\]?

OpenStudy (anonymous):

yes, see i didnt know how to do it that way

OpenStudy (anonymous):

I am new to this, i am just trying to learn new things, I need help

OpenStudy (anonymous):

how do i use the quadratic equation

OpenStudy (anonymous):

how do i use quadratic equation and how do i check the replies

OpenStudy (anonymous):

i need to know the steps and how to get the answer im lost

OpenStudy (anonymous):

2x^2+3x+1 here a=2 the coefficient of x^2 b=3 coefficient of x c= 1 now quadratic formula is: \[(-b \pm \sqrt{b^2-4ac})/2a\]

OpenStudy (anonymous):

put the values to get the answer/solution good enough ??

OpenStudy (anonymous):

she said the answer is (2x+1) (x+1)

OpenStudy (anonymous):

so what is all of that extra work

OpenStudy (anonymous):

sister it can be done by many ways the way i m following is called solving a quadratic eq by quadratic formula maybe she is using mid-term breaking method

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

is there anyother thing you wanna ask regarding the quadratic equation ???

OpenStudy (anonymous):

annas i think she is asking about guess and check not quadratic equations becasu eif the answer she gave before

OpenStudy (anonymous):

because** of**

OpenStudy (anonymous):

yes megan thats what i need help on

OpenStudy (anonymous):

have you learned FOIL yet?

OpenStudy (anonymous):

yes,

OpenStudy (anonymous):

you have to solve it to get the answer there is no guess and check thing in quadratic equations ok but you can surely verify your answer by putting the values in it if 0=0 this means your roots satisfy your equation ...

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

so say you would foil (5x -3) ( 2x+1) you would get \[10x ^{2} - x - 3 \] so say you wopuld guess and check you would get what you foiled \[10x ^{2} - x - 3 \] what times what = 10 well 5 and 2 do so put them there and nothing goes into 3 so you would do 1 and 3

OpenStudy (anonymous):

can yall send me your email at Chopcity313@yahoo.com just in case i get stuck again, i have to make a run for a family emergency just got a call

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