OpenStudy (anonymous):

Can someone help me with this algebra?

6 years ago
OpenStudy (anonymous):

Is there anyone who is very good at algebra with factoring by using trial factors

6 years ago
OpenStudy (anonymous):

the problem is 2x2+3x+1

6 years ago
OpenStudy (anonymous):

\[2x^{2}+3x+1\]?

6 years ago
OpenStudy (anonymous):

yes, see i didnt know how to do it that way

6 years ago
OpenStudy (anonymous):

I am new to this, i am just trying to learn new things, I need help

6 years ago
OpenStudy (anonymous):

how do i use the quadratic equation

6 years ago
OpenStudy (anonymous):

how do i use quadratic equation and how do i check the replies

6 years ago
OpenStudy (anonymous):

i need to know the steps and how to get the answer im lost

6 years ago
OpenStudy (anonymous):

2x^2+3x+1 here a=2 the coefficient of x^2 b=3 coefficient of x c= 1 now quadratic formula is: \[(-b \pm \sqrt{b^2-4ac})/2a\]

6 years ago
OpenStudy (anonymous):

put the values to get the answer/solution good enough ??

6 years ago
OpenStudy (anonymous):

she said the answer is (2x+1) (x+1)

6 years ago
OpenStudy (anonymous):

so what is all of that extra work

6 years ago
OpenStudy (anonymous):

sister it can be done by many ways the way i m following is called solving a quadratic eq by quadratic formula maybe she is using mid-term breaking method

6 years ago
OpenStudy (anonymous):

oh ok

6 years ago
OpenStudy (anonymous):

is there anyother thing you wanna ask regarding the quadratic equation ???

6 years ago
OpenStudy (anonymous):

annas i think she is asking about guess and check not quadratic equations becasu eif the answer she gave before

6 years ago
OpenStudy (anonymous):

because** of**

6 years ago
OpenStudy (anonymous):

yes megan thats what i need help on

6 years ago
OpenStudy (anonymous):

have you learned FOIL yet?

6 years ago
OpenStudy (anonymous):

yes,

6 years ago
OpenStudy (anonymous):

you have to solve it to get the answer there is no guess and check thing in quadratic equations ok but you can surely verify your answer by putting the values in it if 0=0 this means your roots satisfy your equation ...

6 years ago
OpenStudy (anonymous):

oh okay

6 years ago
OpenStudy (anonymous):

so say you would foil (5x -3) ( 2x+1) you would get \[10x ^{2} - x - 3 \] so say you wopuld guess and check you would get what you foiled \[10x ^{2} - x - 3 \] what times what = 10 well 5 and 2 do so put them there and nothing goes into 3 so you would do 1 and 3

6 years ago
OpenStudy (anonymous):

can yall send me your email at Chopcity313@yahoo.com just in case i get stuck again, i have to make a run for a family emergency just got a call

6 years ago
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