What about this one @Diyadiya Given the following perfect square trinomial, fill in the missing term. x^2 − 16x + ____
So it would be 8?
Do using the discriminant method b^2 - 4ac =0 (since it is a perfect square trinomial ) and find c
(-16)^2 -4*1*c =0
can you continue ?
What is (-16)^2 ?
clearly it would be something like (ax + b)^2 expand to get (a^2)(x^2) + b^2 + 2abx so a^2 = 1 and 2ab = 16 i.e. ab = 8 a= 1 or -1 so if a =1 then b=8 and if a = -1, b = -8 so it is (-x - 8)^2 or (x + 8)^2 also we can write the first as [(-1)^2](x+8)^2 which is (x+8)^2 so both the answers are same and the final answer is (x+8)^2
256 - 4*1*c =0 256 - 4c =0 add 4c on both sides 256 - 4c +4c =4c 256 = 4c Now divide both sides by 4 what do you get?
Yes 64 is the missing term :)
So you square then divide.
Square ? No Use this formula b^2 - 4ac =0 (Since its PST ) Substitute the values of b , a & c (here we have to find c ,so let c remain like that )
@careless850 didn't you get my way...??
Tooo complicated. i like the abc method.
ok.....do as u are comfortable with...
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