What about this one @Diyadiya
Given the following perfect square trinomial, fill in the missing term.
x^2 − 16x + ____
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OpenStudy (anonymous):
1
OpenStudy (anonymous):
So it would be 8?
OpenStudy (diyadiya):
Do using the discriminant method
b^2 - 4ac =0 (since it is a perfect square trinomial )
and find c
OpenStudy (diyadiya):
(-16)^2 -4*1*c =0
OpenStudy (diyadiya):
can you continue ?
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OpenStudy (diyadiya):
What is (-16)^2 ?
OpenStudy (savvy):
clearly it would be something like (ax + b)^2
expand to get (a^2)(x^2) + b^2 + 2abx
so a^2 = 1 and 2ab = 16 i.e. ab = 8
a= 1 or -1 so if a =1 then b=8
and if a = -1, b = -8
so it is
(-x - 8)^2 or (x + 8)^2
also we can write the first as [(-1)^2](x+8)^2
which is (x+8)^2
so both the answers are same and the final answer is (x+8)^2
OpenStudy (anonymous):
256
OpenStudy (diyadiya):
256 - 4*1*c =0
256 - 4c =0
add 4c on both sides
256 - 4c +4c =4c
256 = 4c
Now divide both sides by 4
what do you get?
OpenStudy (anonymous):
64
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OpenStudy (diyadiya):
Yes 64 is the missing term :)
OpenStudy (anonymous):
Ohh.....
OpenStudy (anonymous):
So you square then divide.
OpenStudy (diyadiya):
Square ? No
Use this formula b^2 - 4ac =0 (Since its PST )
Substitute the values of b , a & c (here we have to find c ,so let c remain like that )
OpenStudy (anonymous):
I see
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OpenStudy (savvy):
@careless850 didn't you get my way...??
OpenStudy (diyadiya):
:)
OpenStudy (anonymous):
@Savvy No.
OpenStudy (anonymous):
Tooo complicated. i like the abc method.
OpenStudy (savvy):
ok.....do as u are comfortable with...
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