a theatre has 30 rows of seats. there are 16 seats in the first row and each additional row has 2 more seats than the previous row. Seats are allocated randomly to all theatre patrons. Calculate the probability that a randomly chosen patron will be seated in the last row of the theatre

gabby, what course are you taking?

there are several parts to this question firstly the seating forms an arithmetic sequence you have a = 16, d = 2 and n = 30 you will need to find the sum of the seats in the theatre use \[s _{n} = \frac{n}{2}[2a + (n -1)d]\] then you will need to find the number of seats in the 30th row \[T _{n} = a +(n -1) d\] this information will be needed for the probability question P( last row seat) = (number of seats in the last row)/(total number of seats) hope this helps

I'm taking pre calc sorry for the late response

Yeah it did help thanks ! (: