Mathematics OpenStudy (callisto):

Uncategorized question #1 Given that the decimal part of $5+\sqrt{11}$ is A and the decimal part of $5-\sqrt{11}$ is B. Let C=A+B, find the value of C. OpenStudy (anonymous):

Decimal part is the fraction part right? OpenStudy (experimentx):

1?? OpenStudy (callisto):

Fraction?! seems not... The answer I've written is 1.. I forgot how did I get the answer :| OpenStudy (anonymous):

Then what is the decimal part? OpenStudy (callisto):

The square root... OpenStudy (anonymous):

I don't understand. What is the decimal part of 434.4545343434 ? 0.4545343434 isn't? OpenStudy (callisto):

$5+\sqrt{11} = 8.31662479....$ decimal part = 0.31662479.... OpenStudy (anonymous):

Yes that's the fractional part of the number. OpenStudy (anonymous):

less than 1. OpenStudy (callisto):

Okay... I don't know it can be expressed in a fraction :| OpenStudy (callisto):

But how to solve it? Note: no calculator! OpenStudy (anonymous):

No it can't be, actually programming knowledge terminology affected my answer. OpenStudy (callisto):

Do you mean.... it is not solvable? Or...? OpenStudy (callisto):

I think I can 'solve' it now... thanks....... OpenStudy (anonymous):

It is, C is also a decimal number right? OpenStudy (callisto):

C is 1.... OpenStudy (anonymous):

I am getting 1.28571 :/ OpenStudy (anonymous):

9/7 actually OpenStudy (callisto):

._. $5-\sqrt{11} = 1.68337521.....$ B= 0.68337521.... OpenStudy (callisto):

The solution is actually... quite simple :| OpenStudy (anonymous):

:| OpenStudy (callisto):

Should I post it? OpenStudy (anonymous): OpenStudy (callisto):

$5+\sqrt{11}=5+3+A$$5−\sqrt{11}=1+B$Add them.. $10=(5+3+A)+(1+B)$$A+B=1$ This should be better :| OpenStudy (experimentx):

Ah ... nice solution!! I had the intuition ... but couldn't think it would be so simple!! OpenStudy (anonymous):

How $$5−\sqrt{11}=1+B$$ ? :| OpenStudy (anonymous):

Got it :| OpenStudy (callisto):

sqrt 11 = 3.xxxxxx 5-3.xxxxx = 1.yyyyy OpenStudy (anonymous):

I am suck a fool :| OpenStudy (callisto):

If fool = good, then you are :) OpenStudy (anonymous):

NO, this was so easy :( I was thinking it too hard and in the lines of complicated things :| OpenStudy (anonymous):

*such Good solution Calli~

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