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OpenStudy (anonymous):
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OpenStudy (binary3i):
\[(6x-5x)/30 =1/3\] \[3x=30\]\[x=10\]
OpenStudy (ajprincess):
x/5-x/6=1/3 (6*x-5*x)/(6*5)=1/3 (6x-5x)/30=1/3 x/30=1/3 x=(30*1)/3 x=10
OpenStudy (anonymous):
ok here we go... x/5 - x/6 = 1/3 (6x-5x)/30 = 1/3 x/30 = 1/3 x = 30/3 x = 10 Hope this helped !!
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