Question

Twenty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to twelve percent salt?
3 lb
5 lb
12 lb

Answer 1

3 right

Answer 2

yep

Answer 3

ok thanks

Answer 4

hey, wait

Answer 5

answer will be 5 lb

Answer 6

@tylertriebs

Answer 7

Lets see how this is worked out. 20 pounds of water which is 15 % salt. that would mean there is (.15)(20) or 3 pounds of salt. Now we want to add water so that this 3 pounds of water is 12 % of the mixture:
3=.12x
x=3/.12=25 pound mixture. We have 20 already so we only need to add 25-20 or 5 pounds.

Answer 8

hiiiiiiiiiiiiiiii