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Mathematics
OpenStudy (anonymous):

(4y^2-1)/(2y^2+3y-2) can someone up this in simplified form please?

OpenStudy (anonymous):

can you factor the top?

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

want me to type out the answers?

OpenStudy (anonymous):

hehe...:)

OpenStudy (anonymous):

b) (2y+1)/(y+2) with the restrictions y ≠ 1/2 and y ≠ 2

OpenStudy (anonymous):

0a) (2y-1)/(y-2) with the restrictions y ≠ - 1/2 and y ≠ -2

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