Question

(4y^2-1)/(2y^2+3y-2) can someone up this in simplified form please?....

Answer 1

a) (2y-1)/(y-2) with the restrictions y ≠ - 1/2 and y ≠ -2

b) (2y+1)/(y+2) with the restrictions y ≠ 1/2 and y ≠ 2

c) (2y+1)/(y+2) with the restriction y ≠ - 1/2 and y ≠ 2

D) (2y+1)/(y+2) with the restriction y ≠ ½ and y ≠ -2

Answer 2

i think the answer is B or D someone please help.

Answer 3

what is the restriction given for D?

Answer 4

restriction y ≠ ½ and y ≠ -2?

Answer 5

It's D. if y=-2 then the denominator bcums 0 and the whole expression bcums infinity coz 1/0 is infinity.