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OpenStudy (anonymous):

(4y^2-1)/(2y^2+3y-2) can someone up this in simplified form please?....

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OpenStudy (anonymous):

a) (2y-1)/(y-2) with the restrictions y ≠ - 1/2 and y ≠ -2 b) (2y+1)/(y+2) with the restrictions y ≠ 1/2 and y ≠ 2 c) (2y+1)/(y+2) with the restriction y ≠ - 1/2 and y ≠ 2 D) (2y+1)/(y+2) with the restriction y ≠ ½ and y ≠ -2

OpenStudy (anonymous):

i think the answer is B or D someone please help.

OpenStudy (ajprincess):

what is the restriction given for D?

OpenStudy (anonymous):

restriction y ≠ ½ and y ≠ -2?

OpenStudy (ajprincess):

It's D. if y=-2 then the denominator bcums 0 and the whole expression bcums infinity coz 1/0 is infinity.

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OpenStudy (ajprincess):

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