Question

f(x)' x√x

Answer 1

hmm?

Answer 2

\[\Large \sqrt{x}=x^ \frac{1}{2}\]Do you know this?

Answer 3

ya
.. i know derivite of that is 1/2√x

Answer 4

The easier way is to do by this metho\[\Large x \sqrt{x}= x.x^ \frac{1}{2}\]

Answer 5

ok.. then?

Answer 6

\[\Large x^m \times x^n = x^{m+n}\]

Answer 7

\[\Large x \times x^ \frac{1}{2}= ?\]

Answer 8

x^3/2

Answer 9

0_o.. didn;t think of that..but aren't u supposed to use roduct rule?

Answer 10

product rule

Answer 11

no product rule is not applicable here
3/2 x^1/2 answer

Answer 12

now that makes sense 0_o

Answer 13

Yes you can use product rule ,You'll get the same answer

Answer 14

why not tough?

Answer 15

:o ok

Answer 16

thx

Answer 17

\[3/2x^{1/2}\]

Answer 18

\[\frac{d}{dx}x \sqrt{x}=x \frac{d}{dx}\sqrt{x}+\sqrt{x}\frac{d}{dx}x\]\[=x .\frac{1}{2\sqrt{x}}+\sqrt{x}=\frac{x}{2\sqrt{x}}+\sqrt{x} =\frac{\sqrt{x}}{2}+\sqrt{x}\]\[=\frac{\sqrt{x}}{2}+ \frac{\sqrt{x}}{1}=\frac{\sqrt{x}}{2}+\frac{\sqrt{x} \times 2 }{1 \times 2} =\frac{\sqrt{x}}{2}+\frac{2\sqrt{x}}{2}=\frac{3\sqrt{x}}{2}\]

Answer 19

Using the Product Rule^^

Answer 20

wow diya you are really good at maths :)

Answer 21

\[\Large \frac{3}{2}x^ \frac{1}{2}= \frac{3}{2}\sqrt{x}= \frac{3\sqrt{x}}{2}\]Same answer! :)

Answer 22

Lol Thanks Annas!

Answer 23

welcome !

Answer 24

lol ye.. ur really good

Answer 25

hmm hey, if u dont mind can u help me with another question =/?

Answer 26

Post another question :)

Answer 27

ok