Question

What is a shadow generating function?

Answer 1

shadow of what?

Answer 2

and on what?

Answer 3

Sounds like you're describing vector projection...

Answer 4

look at page 4 of: https://docs.google.com/viewer?a=v&q=cache:S9HzZ1KFxpwJ:cdn.transtutors.com/UploadAssignments/63970_1_Port-2012-2013.pdf+%22shadow+generating+function%22&hl=en&gl=uk&pid=bl&srcid=ADGEESgBRzexa6AQ4HpFfUZDq96fA-sldRfp19EtYCwv2G0BOVsokvRW4vu3LDrGqweonXyQts6RtRIaOip9uPvkugcLdBJKsJQUYBzHdljNjl7K8gPmLI87k1EJP9A6Uh-BJeCMnqjA&sig=AHIEtbQKuUaj27361pETt4V2eL9pZhgv-w

Answer 5

Oh wow... interesting. Never heard of that.

Answer 6

Basically it states:

A "shadow function" to \(y_1\) is another quadratic \(y_2\) which shares the same vertex as \(y_1\). However \(y_2\) has opposite concavity to \(y_1\) and its zeros are in the form \(a\pm b\).

Answer 7

That document is exactly what i'm working from... the question i'm referring to is "Hence, or otherwise, express y2 in terms of y1 and ym , where ym is called the “shadow
generating function”." But I don't know how to get ym if i don't know what a shadow generating function is.