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Mathematics
OpenStudy (anonymous):

Factor completely: 2x3y4 − 8x2y3 + 6xy2 2(x3y4 − 4x2y3 + 3xy2) 2x(x2y4 − 4xy3 + 3y2) 2xy2(x2y2 − 4xy + 3) Prime

OpenStudy (anonymous):

The correct answer is 2xy2(x2y2 − 4xy + 3)

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