Question

Find the exact solutions of the given equation in the interval [0,2π]: sin^2x + sin2x = -cos^2x + 1

Answer 1

well, first of all, remember that
\[ \sin^2 x + \cos^2 x = 1\]
Use that to simplify your problem!

Answer 2

\[\sin ^2x+\sin 2x+\cos ^2x-1=0\]
\[1+\sin 2x-1=0\]
\[\sin 2x=0\]

Answer 3

Take it from there.

Answer 4

ok, i will give it a try

Answer 5

i know that 0 would work for a solution, but what is the best way to find the rest of the choices?