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The value 3pi/16 is a solution for the equation 2cos^2(4x)-1=0.
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2cos^2(4*3pi/16) - 1
= 2cos^2(3pi/4) - 1
= 2(-sqrt2/2)^2 - 1
= 2(1/2) - 1
= 1 - 1
maybe i'll just put down the solution as "calculator" the next time... :)
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