Mathematics
OpenStudy (anonymous):

Find the geometric mean of 36 and 16.

OpenStudy (asnaseer):

geometric mean of two numbers a and b is defined as:$\sqrt{a\times b}$

OpenStudy (anonymous):

$\sqrt{36X16}$

OpenStudy (anonymous):

So would i do that?

OpenStudy (asnaseer):

yes

OpenStudy (anonymous):

Hint: $$\sqrt{36 \cdot 16}=\sqrt {36} \sqrt{16}$$

OpenStudy (asnaseer):

you should make use of the fact that:$36=6^2$and$16=4^2$

OpenStudy (anonymous):

so the answer would be 96?

OpenStudy (asnaseer):

how did you get 96?

OpenStudy (anonymous):

the square root of 36X16

OpenStudy (asnaseer):

you can write this as:$\sqrt{36*16}=\sqrt{36}\times\sqrt{16}$ now, what is $$\sqrt{36}$$? and what is $$\sqrt{16}$$?

OpenStudy (anonymous):

6 and 4

OpenStudy (asnaseer):

correct, so you would get:$\sqrt{36*16}=\sqrt{36}\times\sqrt{16}=6*4=?$

OpenStudy (anonymous):

so the geometric mean of 36 and 16 is 24?

OpenStudy (asnaseer):

correct

OpenStudy (anonymous):

all right thx c:

OpenStudy (asnaseer):

yw