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Find the geometric mean of 36 and 16.
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geometric mean of two numbers a and b is defined as:\[\sqrt{a\times b}\]
\[\sqrt{36X16}\]
So would i do that?
yes
Hint: \(\sqrt{36 \cdot 16}=\sqrt {36} \sqrt{16}\)
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you should make use of the fact that:\[36=6^2\]and\[16=4^2\]
so the answer would be 96?
how did you get 96?
the square root of 36X16
you can write this as:\[\sqrt{36*16}=\sqrt{36}\times\sqrt{16}\] now, what is \(\sqrt{36}\)? and what is \(\sqrt{16}\)?
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6 and 4
correct, so you would get:\[\sqrt{36*16}=\sqrt{36}\times\sqrt{16}=6*4=?\]
so the geometric mean of 36 and 16 is 24?
correct
all right thx c:
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yw
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