Mathematics OpenStudy (anonymous):

Find the geometric mean of 36 and 16. OpenStudy (asnaseer):

geometric mean of two numbers a and b is defined as:$\sqrt{a\times b}$ OpenStudy (anonymous):

$\sqrt{36X16}$ OpenStudy (anonymous):

So would i do that? OpenStudy (asnaseer):

yes OpenStudy (anonymous):

Hint: $$\sqrt{36 \cdot 16}=\sqrt {36} \sqrt{16}$$ OpenStudy (asnaseer):

you should make use of the fact that:$36=6^2$and$16=4^2$ OpenStudy (anonymous):

so the answer would be 96? OpenStudy (asnaseer):

how did you get 96? OpenStudy (anonymous):

the square root of 36X16 OpenStudy (asnaseer):

you can write this as:$\sqrt{36*16}=\sqrt{36}\times\sqrt{16}$ now, what is $$\sqrt{36}$$? and what is $$\sqrt{16}$$? OpenStudy (anonymous):

6 and 4 OpenStudy (asnaseer):

correct, so you would get:$\sqrt{36*16}=\sqrt{36}\times\sqrt{16}=6*4=?$ OpenStudy (anonymous):

so the geometric mean of 36 and 16 is 24? OpenStudy (asnaseer):

correct OpenStudy (anonymous):

all right thx c: OpenStudy (asnaseer):

yw

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