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OpenStudy (anonymous):

What is the period, in seconds, of a simple pendulum of length 2 meters? Use the gravitational constant g = 9.8 m/s2 and round your answer to two decimal places.

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OpenStudy (anonymous):

\[T=2\pi*\sqrt{L/g}\] \[T=2\pi*\sqrt{2/9.8}\] \[T=2\pi*(0.4517539515)\] \[T=2.84s\]

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