Question

What is the period, in seconds, of a simple pendulum of length 2 meters? Use the gravitational constant g = 9.8 m/s2 and round your answer to two decimal places.

Answer 1

\[T=2\pi*\sqrt{L/g}\]
\[T=2\pi*\sqrt{2/9.8}\]
\[T=2\pi*(0.4517539515)\]
\[T=2.84s\]