Question

Please help me with this! Simplify the following quotient of complex numbers into the form a+bi. -9 + 2i / -8 - 9i

Answer 1

In this type of problem, always multiply by the conjugate of the denominator.

Answer 2

unfortunately... you just spoke a completely different language to me

Answer 3

We are trying to set up a situation in the denominator which will eliminate the radical. If we can have a (a-b)(a+b) product, that will do the trick.

Answer 4

Since the denominator is -8-9i we need to multiply that by -8+9i which is called the conjugate of -8-9i

Answer 5

so -9+2i / -8-9i(-8+9i)?

Answer 6

Must multiply the numerator by the same thing.

Answer 7

\[\frac{-9+2i}{-8-9i}\times\frac{-8+9i}{-8+9i}\]

Answer 8

-9+2i(-8+9i) / -8-9i(-8+9i)

Answer 9

No. The first denominator is -8-9i

Answer 10

is that not what I put?

Answer 11

Just look at you next to last post.

Answer 12

ugh.... Im so bad at math

Answer 13

i got -72+18i