Please help me with this! Simplify the following quotient of complex numbers into the form a+bi. -9 + 2i / -8 - 9i

Question

mertsj · Answer

In this type of problem, always multiply by the conjugate of the denominator.

anonymous · Answer

unfortunately... you just spoke a completely different language to me

mertsj · Answer

We are trying to set up a situation in the denominator which will eliminate the radical.  If we can have a (a-b)(a+b) product, that will do the trick.

mertsj · Answer

Since the denominator is -8-9i we need to multiply that by -8+9i which is called the conjugate of -8-9i

anonymous · Answer

so -9+2i / -8-9i(-8+9i)?

mertsj · Answer

Must multiply the numerator by the same thing.

mertsj · Answer

$$\frac{-9+2i}{-8-9i}\times\frac{-8+9i}{-8+9i}$$

anonymous · Answer

-9+2i(-8+9i) / -8-9i(-8+9i)

mertsj · Answer

No.  The first denominator is -8-9i

anonymous · Answer

is that not what I put?

mertsj · Answer

Just look at you next to last post.

anonymous · Answer

ugh.... Im so bad at math

anonymous · Answer

i got -72+18i

mertsj · Answer

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