Please help me with this! Simplify the following quotient of complex numbers into the form a+bi. -9 + 2i / -8 - 9i
In this type of problem, always multiply by the conjugate of the denominator.
unfortunately... you just spoke a completely different language to me
We are trying to set up a situation in the denominator which will eliminate the radical. If we can have a (a-b)(a+b) product, that will do the trick.
Since the denominator is -8-9i we need to multiply that by -8+9i which is called the conjugate of -8-9i
so -9+2i / -8-9i(-8+9i)?
Must multiply the numerator by the same thing.
-9+2i(-8+9i) / -8-9i(-8+9i)
No. The first denominator is -8-9i
is that not what I put?
Just look at you next to last post.
ugh.... Im so bad at math
i got -72+18i
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