Mathematics OpenStudy (anonymous):

write a quadratic equation in the variable x having the given number as solutions. Type in standard form, ax^2+bx+c=0. Solution; 2, only solution. OpenStudy (anonymous):

(x-2)*(x-2)=0 expand it OpenStudy (anonymous):

x^2-4*x+4 OpenStudy (anonymous):

x^2-4*x+4=0 Parth (parthkohli):

Well, one solution: \(\Large \color{Black}{\Rightarrow (x + 2)^2 = 0 }\) \(\Large \color{Black}{\Rightarrow x^2 + 4x + 4 = 0 }\) Two solutions: \(\Large \color{Black}{\Rightarrow (x + 2)(x + 1) = 0 }\) \(\Large \color{Black}{\Rightarrow x(x + 1) + 2(x + 1) = 0 }\) \(\Large \color{Black}{\Rightarrow x^2 + x + 2x + 2 = 0 }\) \(\Large \color{Black}{\Rightarrow x^2 + 3x + 2 = 0 }\) OpenStudy (anonymous):

Thank you! OpenStudy (anonymous): OpenStudy (anonymous):

it is (x-2)^2=0 if you pick plus 2 then solution will be -2 not 2 OpenStudy (anonymous):

@ParthKohli it is (x-2)^2=0 if you pick plus 2 then solution will be -2 not 2 Parth (parthkohli):

Oh I thought we were talking about number of solutions haha OpenStudy (anonymous):

Thats better than the answer I arrived at. ha OpenStudy (anonymous):

x^2-4*x+4=0

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