Question

write a quadratic equation in the variable x having the given number as solutions. Type in standard form, ax^2+bx+c=0. Solution; 2, only solution.

Answer 1

(x-2)*(x-2)=0 expand it

Answer 2

x^2-4*x+4

Answer 3

x^2-4*x+4=0

Answer 4

Well, one solution:

\(\Large \color{Black}{\Rightarrow (x + 2)^2 = 0 }\)
\(\Large \color{Black}{\Rightarrow x^2 + 4x + 4 = 0 }\)

Two solutions:

\(\Large \color{Black}{\Rightarrow (x + 2)(x + 1) = 0 }\)
\(\Large \color{Black}{\Rightarrow x(x + 1) + 2(x + 1) = 0 }\)
\(\Large \color{Black}{\Rightarrow x^2 + x + 2x + 2 = 0 }\)
\(\Large \color{Black}{\Rightarrow x^2 + 3x + 2 = 0 }\)

Answer 5

Thank you!

Answer 6

https://www.google.com/search?rlz=1C1CHFX_enUS470US470&sugexp=chrome,mod=17&sourceid=chrome&ie=UTF-8&q=(x-2)*(x-2)

Answer 7

it is (x-2)^2=0

if you pick plus 2 then solution will be -2 not 2

Answer 8

@ParthKohli
it is (x-2)^2=0

if you pick plus 2 then solution will be -2 not 2

Answer 9

Oh I thought we were talking about number of solutions haha

Answer 10

Thats better than the answer I arrived at. ha

Answer 11

x^2-4*x+4=0