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Chemistry
OpenStudy (anonymous):

Keq for this reaction is 3.63. A + 2B  C The data in the table shows the concentrations of the reactants and product in two different reaction mixtures at the same temperature. Does the data provide evidence that both reactions are at equilibrium? Concentrations of A, B and C A (mol/L) B (mol/L) C (mol/L) 0.500 0.621 0.700 0.250 0.525 0.250 a.) No, the data give different Keq values b.) No, the concentration of C is lower than B in the second mixture c.) Yes the Keq remains constant d.) Yes, there is always produ

OpenStudy (anonymous):

product present*

OpenStudy (anonymous):

c.) Yes the Keq remains constant you need to calcuate Keq and you will see that it is the same in both cases: Keq= C/(A*B^2) = 3,63

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