Question

__ pi/3 sin pi/6=1/2(sin pi/2-sin pi/6)

Im confused?

Answer 1

Perhaps this identity helps?
\[cosAsinB = \frac{1}{2}[sin(A+B)-sin(A-B)]\]

Answer 2

but i'm still confused on the question?

Answer 3

Now, you have two angle.
Consider the left side,
A = pi/3
B = pi/6
Try to apply this in the identity, and you'll see something