Question

The values of x satisfying the equation 8x^3/2n - 8x^-3/2n = 63 are?

Answer 1

@Callisto @experimentX @badi @dpaInc @FoolForMath @JamesJ @jerwyn_gayo

Answer 2

The answer should be 2^2n and 1/(2^2n)

Answer 3

let, x^3 = u

Answer 4

ok

Answer 5

x^-3 = 1/u and solve quadratic equation

Answer 6

It is not cube it is x^(3/2n)

Answer 7

@experimentX

Answer 8

oh .. i believe both 3 is 3n??

Answer 9

Is this your equation?\[8x^{\frac{3}{2n}} - 8x^{-\frac{3}{2n}} = 63 \]

Answer 10

yes

Answer 11

So the 8 is not affected by the exponent, only the x?

Answer 12

\[8x^{\frac{3}{2n}} - 8x^{-\frac{3}{2n}} = 63\]\[x^{\frac{3}{2n}}(8x^{\frac{3}{2n}} - 8x^{-\frac{3}{2n}}) = 63(x^{\frac{3}{2n}})\]\[8x^{2(\frac{3}{2n})} - 8 = 63x^{\frac{3}{2n}}\]\[8x^{2(\frac{3}{2n})} -63x^{\frac{3}{2n}} - 8 = 0\]\[(8x^{\frac{3}{2n}}+1)(x^{\frac{3}{2n}}-8)=0\]\[(8x^{\frac{3}{2n}}+1)=0 \ or\ (x^{\frac{3}{2n}}-8)=0\]\[x^{\frac{3}{2n}} = -0.125 \ or \ x^{\frac{3}{2n}} =8\]

Answer 13

That's weird :|