Mr.Bob is playing a game.The rule of the game is the following .Bob has first to throw a die.When the die appears with number X, Bob has chance to open X boxes among 10. Among the 10 boxes, there are two boxes containing the prize of $500, one box containing $1000, and the other boxes are empty. If he gets the prize boxes, he gets the prize.
a.Find the probability for him to win the prize.
b.How much would he expect to win the prize.
c.Suppose that the die thrown by Bob appeared with number 4, and that he has opened three empty boxes already.How much would he expect to win the prize?

Question

Mr.Bob is playing a game.The rule of the game is the following .Bob has first to throw a die.When the die appears with number X, Bob has chance to open X boxes among 10. Among the 10 boxes, there are two boxes containing the prize of $500, one box containing $1000, and the other boxes are empty. If he gets the prize boxes, he gets the prize.
a.Find the probability for him to win the prize.
b.How much would he expect to win the prize.
c.Suppose that the die thrown by Bob appeared with number 4, and that he has opened three empty boxes already.How much would he expect to win the prize?

anonymous · Answer

can you tell me how can i select 4 boxes out of 10 so that i can get a prize

anonymous · Answer

hello....is there anyone???

anonymous · Answer

yeah is i get to choose 4 out of 10 boxes the probability i get at least one prize is $1-\frac{7}{10}\times \frac{6}{9}\times \frac{5}{8}\times \frac{4}{7}$

anonymous · Answer

and of course the probability i get to choose 4 boxes is $\frac{1}{6}$

anonymous · Answer

which gives a good idea of what a general solution might look like.

anonymous · Answer

sry but you might be wrong

anonymous · Answer

You are so clever,but could you give the probability for him to win the prize.
 Thank in advance for your help.