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OpenStudy (anonymous):

11. A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder, h, in feet after t seconds is given by the function . How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary. (1 point)

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OpenStudy (anonymous):

\[h = -16t ^{2} + 148t +30\]

OpenStudy (anonymous):

That is the function ^^

OpenStudy (anonymous):

At the maximum height v = 0. Try finding t from there and then substitue. OR At maxima/ minima, dh/dt = 0 -32t + 148 = 0 t = 4.625

OpenStudy (anonymous):

Now substitute t in the function as d^2h/dt^2 is negative => maxima.

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