11. A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder, h, in feet after t seconds is given by the function . How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary. (1 point)

Question

11.   A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder, h, in feet after t seconds is given by the function . How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary.  (1 point)

anonymous · Answer

$$h = -16t ^{2} + 148t +30$$

anonymous · Answer

That is the function ^^

anonymous · Answer

At the maximum height v = 0.
Try finding t from there and then substitue.
OR
At maxima/ minima,
dh/dt = 0
-32t + 148 = 0
t = 4.625

anonymous · Answer

Now substitute t in the function as d^2h/dt^2 is negative => maxima.