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Factor completely: x2 − 4x + 9 (x − 1)(x − 9) (x − 3)(x − 3) (x + 3)(x − 3) Prime
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I see it as prime :/
How can we factor this?
You can even multiply all options, and you won't get the desired result.
if b^2-4ac is not a perfect square, the expression is prime
Yes, the discriminant.
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