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Mathematics 13 Online
OpenStudy (anonymous):

Factor completely: x2 − 4x + 9 (x − 1)(x − 9) (x − 3)(x − 3) (x + 3)(x − 3) Prime

Parth (parthkohli):

I see it as prime :/

Parth (parthkohli):

How can we factor this?

Parth (parthkohli):

You can even multiply all options, and you won't get the desired result.

OpenStudy (anonymous):

if b^2-4ac is not a perfect square, the expression is prime

Parth (parthkohli):

Yes, the discriminant.

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