Question

Area of a rectangular playground is 20 squared yards. The length is 5 times longer, than its width. Find the length and width of the playground.

Answer 1

Well so basically length is 5x and width is x. area = l * w, so

\(\Large \color{Black}{\Rightarrow 5x \times x = 20 }\)
\(\Large \color{Black}{\Rightarrow 5x^2 = 20 }\)
\(\Large \color{Black}{\Rightarrow x^2 = 4 }\)
\(\Large \color{Black}{\Rightarrow x = 2 }\)

So the width is x = 2
length is 2 * 5 = 10

Answer 2

can you also help me solve an eqution?

Answer 3

equation*

Answer 4

Sure. Yes.

Answer 5

x^2 + 3 = 9x

i know it's going to be;

x^2 - 9x + 3 = 0

Answer 6

then;

a= 1
b= -9
c= 3

Answer 7

Hmm correct

Answer 8

Use the quadratic formula.

Answer 9

Do you know what the formula is?

Answer 10

It is:

\(\Large \color{Black}{\Rightarrow x = {-b \pm \sqrt{b^2 - 4ac} \over 2a} }\)

Answer 11

\[x = -b \pm \sqrt{b ^{2} - 4ac} / 2a\]

Answer 12

yes:)

Answer 13

i got 13.15 & 4.85

Answer 14

but it doesn't equal 0

Answer 15

Wolfram in this case :)

Answer 16

lol what? :)

Answer 17

Hehe http://www.wolframalpha.com/input/?i=x%5E2+-+9x+%2B+3+%3D+0

Answer 18

so what is the answer? im confused lol