Question

Take the fraction and transform it into the sum or two fractions (method of partial fractions): (4x+3)/(x^2-x-6)

Answer 1

= 4x + 3 A B
-------- = ---- + -----
(x - 3)(x + 2) (x - 3) (x + 2)
multiply thru by (x-3)(x+2)

4x + 3 = A(x+2) + B(x-3)
let x = 3 then
15 = 5A
let x = -2 then
-5 = -5B

solve these 2 simple equations to get your partial fractions