Take the fraction and transform it into the sum or two fractions (method of partial fractions): (4x+3)/(x^2-x-6)

Question

cwrw238 · Answer

=    4x + 3                   A                B
     --------         =   ----   +     -----
    (x - 3)(x + 2)          (x - 3)         (x + 2)
 multiply thru by (x-3)(x+2)

 4x + 3  = A(x+2) + B(x-3)
let x = 3 then 
15 = 5A
let x = -2 then
-5 = -5B

solve these 2 simple equations to get your partial fractions