Question

How do you find the velocity of an object on top of a loop?

Answer 1

If you know the velocity in the bottom of the loop, then
\[ \frac{1}{2}m{v_b}^2 = \frac{1}{2}m{v_t}^2 + mg2r \]
rearranging the term, we get
\[ v_t = \left( {v_b}^2 - 4gr \right)^{\frac{1}{2}} \]

Answer 2

Thank you!!