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g(x)= x-√x+2 a) find the least value of x for which there is a real number value of f(x) b) Sketch the graph using a suitable domain c) Find the x intercept d) Find the g(x) intercept
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√x is real only if x ≥ 0 so the smallest value of x would be 0 there is no x intercept since the smallest value of g(x) = g(.25) = 1.75 g(x) intercept is g(0) = 2
What would the values be if g(x)=-2?
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