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|dw:1338271037816:dw|
how can i find the x
\[c ^{2} = a ^{2} + b ^{2} = 8^{2} + 10^{2} = 64 + 100 = 164\]
lol i thought 10 was the hypotenus :/
\[x = \sqrt{164} = \sqrt{4 * 41} = 2\sqrt{41}\]
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thx
you can use trig functions to solve for angles
I know how to solve for y and z but thx anyways.
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