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In the above figure, find 2m
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A. 150
i thought it was c.
m<AEC = 47 + 28 = 75 2m<AEC = 2(75) = 150
ok i dint know that you had to add 47 and 28.
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Yeah.
thank you for teaching me how to solve this problem
You're welcome
do we do the samething for this one. find m<aec+3m<bec
m<aec will = 75 and bec will =141 and thn you add them and the answer would be 216. am i right?
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m<BEC = 47 not 141. Then, if you add them, you would get 122
I don't get why you would do that though.
but i though you have to * by 3
i thought that you had to 47*3= 141
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