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If 2tan x/1-tan^2 x =1 then x can equal: (More than 1 answer) a. x=7pi/8+ n(pi) b. x=pi/8+ n(pi) c. x=3pi/8+ n(pi) d. x=5pi/8+ n(pi)
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Try factoring your expression, as if you were treating \(\tan x\) as a single variable.
\[\frac{2\tan x}{1-\tan^2 x} = \tan 2x \]
ans is b tan2x = 1 hence, 2x = 3.14/4 + 2*n*3.14
is there another answer then b though?
Whoops...interpreted your question incorrectly since you didn't use parenthesis...follow @FoolForMath 's reasoning.
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The simplest way is to check via options.
well we know B. is part of the answer but what about D?
D is also correct answer
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