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Find the value of sqrt 8\9
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\(\Large \color{Black}{\Rightarrow \sqrt{8 \over 9} = {\sqrt{8} \over \sqrt{9}} }\)
\[\frac{2}{3} \sqrt{2}\]
\[\large \frac{\sqrt 8}{\sqrt 9} \times \frac{\sqrt 9}{\sqrt 9}\]
72\89?
\(\sqrt 9 \times \sqrt 9 = 9\) \[\sqrt{8 \times 9} = \sqrt{4 \times 2 \times 9} = 2(3)\sqrt 2\]
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