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In △DEF, what is the length of DF A) 90 B) 45 square root 2 C) 15 square root 3 D) 30 square root 3
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h=45sin60
i dont get how to do it????
sin60 = DE/DF DF = 45/sin60 = 45/(√3/3) = 135/√3 = 135√3/3 = 45√3
i give up some one just give me the damn answer
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@hoblos got it. its \[45\sqrt{3}\]
thanks
|dw:1338318827387:dw|
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