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What is the slope of a line perpendicular to x - 3y = 9?
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First, let's convert this into slope-intercept form. \(\Large \color{Black}{\Rightarrow -3y = -x + 9}\) \(\Large \color{Black}{\Rightarrow y = {(x + 9) \over -3} }\) \(\Large \color{Black}{\Rightarrow y = {-1 \over 3} }\) \(\Large \color{Black}{\Rightarrow y = -{x \over 3} - 3 }\) Slope is -1/3. Slope of a line perpendicular to that would be the negative reciprocal. -3/-1 3
3 is the slope of the perpendicular line.
whats a negative reciprocal?
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