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What are the roots of the equation 3x^2-x+2=0
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this equation can be factorised (3x )(x ) = 0 you need 2 numbers to fill blanks in each bracket their product must be = +2 and 3* one of them + the must = -1
and 3* one of them + the other must = -1
ok they are -1 and +2 because 3*-1 + 2 = -1 so can you tell where the -1 and + 2 go in the above brackets?
are you there?
Yes,sorry I was doing something. :)
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Is it (3x+2)(x-1)
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