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\[35\sqrt{50}/7\sqrt{2}\]
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the numerator can be simplified to 35sqrt50 = 35*sqrt(25*2) = 35*5*sqrt2 so (35*5*sqrt2)/(7*sqrt2) = 25 notice the sqrt2 cancels, and the 35 and 7 cancels 5/1 which leaves 5*5 at the numerator...
will you check out my question plz? http://openstudy.com/study#/updates/4fc40f0de4b0964abc86ad6c
\[(5\sqrt{2})(4\sqrt{10})\]
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