Question

f(x)=3x^2-12x+15
Vertex: (2,3)
What is the equation of the line of symmetry: 2
What is the max/min:(2,3)
Is this correct?

Answer 1

For any parabola of the form \(ax^2+bx+c=0 \) the vertex will be at

\( \large \left(-\frac b {2a} , -\frac {b^2-4ac}{4a}\right) \).Equation of line of symmetry will be at \(x=-\frac b {2a} \)

Maximum and minimum values will be at \( \large \left(-\frac b {2a} , -\frac {b^2-4ac}{4a}\right) \) and \( \large \left(-\frac b {2a} , -\frac {b^2-4ac}{4a}\right) \) for \(a<0\) and \(a>0\) respectively.

Answer 2

Ok I will write this down...this is how my teacher did it...