Question

There are 5 red and 9 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probability of choosing 2 red balls and then 1 green ball?
My answer was 225/2744.
am i right????!!!

Answer 1

You are replacing....so it'd be P(red) * P(red) * P(green)

Answer 2

Here are the choices.. sorry forgot to include them :/

Answer 3

I got (5/14)(5/14)(9/14)=225/2744... is that right? or no?? I am confused..

Answer 4

\(\Large \color{Black}{\Rightarrow {5 \times 5 \times 9 \over 14^3 } }\)

\(\Large \color{Black}{\Rightarrow {225 \over 2744} }\)

Correct!